Сазнова Т.Е. учитель начальных классов МОУ СОШ 222 г.Заречный Пензенская обл. Сазнова Т.Е. учитель начальных классов МОУ СОШ 222 г.Заречный Пензенская. - презентация

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2 Сазнова Т.Е. учитель начальных классов МОУ СОШ 222 г.Заречный Пензенская обл. Сазнова Т.Е. учитель начальных классов МОУ СОШ 222 г.Заречный Пензенская обл.

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4 2 – 2 = 3 – 1 = 3 – = 3 + (4 – 1) = = 2 – 1 = = 4 – = 4 – = 2– (4 – 3)= = 4 – 2 = 4 – 3 = = 4 – 1 = = – 2 = 2 – 0 = – 3 = 4 – (4 – 2) = 3 – 2 = 4 – (2 + 1)= =

5 4 – = 4 – = – 2 = = 2– (4 – 3)= 2– (4 – 3)= 4 – = 4 – = 4 – (4 – 2) = – 3 = 3 + (4 – 1) = 4 – (2 + 1)= 3 – = 2 – 1 = = 3 – 1 = = 4 – 2 = 4 – 3 = = 4 – 1 = = 3 – 2 =

6 2 + 2 = 4 – 2 = 4 – = 4 – = – 2 = = 2– (4 – 3)= 2– (4 – 3)= 4 – = 4 – = 4 – (4 – 2) = – 3 = 3 + (4 – 1) = 4 – (2 + 1)= 3 – = 3 – 1 = = 4 – 3 = = 4 – 1 = 3 – 2 =

7 4 – 1 = 4 – = 4 – = – 2 = = 2– (4 – 3)= 2– (4 – 3)= 4 – = 4 – = 4 – (4 – 2) = – 3 = 3 + (4 – 1) = 4 – (2 + 1)= 3 – = 3 – 1 = = 3 – 2 = = 4 – 3 =

8 3 – 2 = 4 – = 4 – = – 2 = = 2– (4 – 3)= 2– (4 – 3)= 4 – = 4 – = 4 – (4 – 2) = – 3 = 3 + (4 – 1) = 4 – (2 + 1)= 3 – = 3 – 1 = =

9 2– (4 – 3)= 2– (4 – 3)= 4 – = 4 – = 4 – (4 – 2) = – 3 = 3 + (4 – 1) = 4 – (2 + 1)= 3 – = 4 – = 4 – = – 2 = =

10 1 3 + (2 – 1) = 4– (4 – 3)= 4 – (4 – 2) = 4 – (2 + 1)=

11 3 + (2 – 1) = 4– (4 – 3)= 4 – (4 – 2) =

12 4– (4 – 3)= 4 – (4 – 2) =

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14 – 1 6 – – 6 6 – – 2 5 – 3 6 – – – 2 5 – 4 5 – 0 5 – – 0 11 – – 10 Составьте обратные примеры

15 7 – 0 5 – – 2 6 – 4 7 – 6 7 – 1 7 – – 3 4 – 2 7 – 5 7 – 4 Найдите «лишние примеры».

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18 4 + 4 = 8 – 5 = = = 8 – 7 = = 8 – 4 = 8 – 3 = = 8 – 6 = 8 – 0 = = 8 – 8 = 8 – 1 = 8 – 2 =

19 9 – – 6 9 – 3 9 – – 4 9 – 8 9 – 5 9 – 2 9 –

20 10 – 1= 10 – 5= 10 – 9= 10 – 6= 10 – 8= = = 4 + 6= 10 – 7= 10 – 2= = = 10– 4= 10 – 3= = –10=

21 3 – 2 3 – 2 7 – 5 7 – – 5 9 – 5 6 – 1 6 – 1 9 – 3 9 – 3 8 – 5 8 – – 3 10 – 3 10–6+3= 3+7–6= = = 5+2+3= 9–7+6= 9–(7–2)= 10-(6+3)= 4+(7–5 )= 3+(2+5)= 8–(10–4)= Решите круговые примеры

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